(3x+3)^2=(x+7)

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Solution for (3x+3)^2=(x+7) equation: 



(3x+3)^2=(x+7)

We move all terms to the left:

(3x+3)^2-((x+7))=0



We calculate terms in parentheses: -((x+7)), so:

(x+7)

We get rid of parentheses

x+7

Back to the equation:

-(x+7)



We get rid of parentheses

(3x+3)^2-x-7=0

We add all the numbers together, and all the variables

-1x+(3x+3)^2-7=0

We move all terms containing x to the left, all other terms to the right

-1x+(3x+3)^2=7

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